Python Challenge level 14: “walk around”
Level 14 is really short once again.
Hint 1: image is a spiral. It’s direction could be meaningful
Hint 2: remember: 100*100 = (100+99+99+98) + …. (3+2+2+1)+1
Fact 1: wire.jpg is 1×10000 pixels = 100*100
I especially liked this level because it was straight forward. You didn’t have to imagine obscure meanings hidden in the hints. The wire.jpg is so streched that it resembles a barcode, so you can automatically know that there is something encoded somehow. Also the 100*100 sequence hint, and the 100*100 pixels couldn’t be clearer. I think it is the first level I solved in under 5 minutes since the easy ones at the beginning of the game.
#!/usr/bin/env python
import Image
im = Image.open("wire.png")
new = Image.new(im.mode,[100,100])
doubled_steps=200
directions=[(1,0), (0,1), (-1,0), (0,-1)] # vectors in [x,y] format
x,y,p=-1,0,0
while doubled_steps//2 > 0:
for v in directions: # we will be taking steps in 4 directions
steps=doubled_steps//2
for s in range(steps):
x,y=x+v[0],y+v[1]
new.putpixel((x,y),im.getpixel((p,0)))
p+=1
doubled_steps-=1
new.save('14.jpg')
It’s a cat. We’ll learn its name in cat.html as well as the place to go if we’re looking for Level 15.
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The double_steps threw me off, but made me study your snippet cos it is way more KISSable than my hack. my ipython log for that session … embarrassing.
Your soln inspired me to write another
Thank you!
Using a generator:
def seqSquare(start): ''' < -- remember: 100*100 = (100+99+99+98) + (... --> >>> assert reduce( lambda x,y: x+y, seqSquare(100)) == 100 * 100 >>> assert reduce( lambda x,y: x+y, seqSquare(50)) == 50 * 50 >>> assert reduce( lambda x,y: x+y, seqSquare(99)) == 99 * 99 ''' yield start while start > 1: start -= 1 yield start yield start def walkywalky(): from PIL import Image imS = Image.open( 'wire.png') imT = Image.new(imS.mode,(100,100)) vector = [ (1,0), (0,1), (-1,0), (0,-1)] x,y,p,v = -1,0,0,0 for steps in seqSquare(100): for step in range(steps): dx,dy = vector[v%4] x,y = x+dx, y+dy # print '(%d, %d) == %d' % (x, y, p) imT.putpixel((x,y),imS.getpixel((p,0))) p += 1 # print v += 1 imT.show()Hey Marcus!
Thanks for the comment. I didn’t think anyone was reading :-)
If you want to talk about embarrassing just wait to level 22. *THEN* we can talk about ugly code! ;)
I’ve been busy this week so I’ve stopped playing at level 24. But I’ll be back soon. I hope the rest of the posts are useful for someone.
Taher,
You’re not kidding! I’m on 24 right now and … I’m hitting a lot of dead ends. … its sucking be back in!
/Marcus
The red pixels threw me off for a while. If you simply stack the rows vertically they spell the word “bit” which takes you to a page that says “you took the wrong curve. Spent a long time after that trying to line up the red pixels another way :)
I got to bit.html and then got the message – ‘you took the wrong curve’. So I must have done the wrapping around incorrectly.
Not clear to me why we are using 200 as the limit. Can you please explain?